### 1 = √[1] = √[(-1) * (-1)] = √[-1] * √[-1] = i * i = iČ = -1. Thus, 1 = -1. QED

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Tejesh

Senior Member

Numbers are so much fun. I used to absolutely pi** off my math teachers in school with dumb stuff like this.

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0neechan

Member

Quote:
Originally Posted by Doghealer
a = 1
b = 1
a = b
a*a = b*a
a^2-b^2=b*a-b^2
(a+b)(a-b)=b(a-b)
a+b=b
2=1

DID I WIN?
..yes, you did

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Blugyblug

Senior Member

Quote:
Originally Posted by Griftrix
In mathematics, isn't technically wrong, exactly wrong?
Integrate (x^3 - 2x^2 -2x -1)/(x^2 -2x-3)

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Doghealer

Senior Member

Quote:
Originally Posted by Blugyblug
Integrate (x^3 - 2x^2 -2x -1)/(x^2 -2x-3)
(log(x+1)+log(x-3)+x^2)/2

EDIT: Totally Shen'd the red.

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Celenphor

Senior Member

Nerds.

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Griftrix

Senior Animation Engineer

Quote:
Originally Posted by Blugyblug
Integrate (x^3 - 2x^2 -2x -1)/(x^2 -2x-3)
1/2 * [ x^2 + log ( -x^2 + 2x + 3 ) ] + constant

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Boyahda

Senior Member

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Griftrix

Senior Animation Engineer

Quote:
Originally Posted by Doghealer
(log(x+1)+log(x-3)+x^2)/2

EDIT: Totally Shen'd the red.
O_o

Given point P and location L, create the look at, up, and right vectors of a camera's orientation matrix that is located at L and looking at point P. You can use Z as up, or whatever you want, just tell me which you're using.

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K rent

Senior Member

Quote:
Originally Posted by Griftrix
It is. But you will only understand that if you understand that 0.9 repeating is a real number, not something that approaches a number. Without that understanding it may be hard to grasp.
1/11=.0909090~~~
2/11=.18181818~~~
3/11=.2727272727~~~
10/11=.90909090~~~~
11/11=.99999999~~~ = 1

You are essentially adding .0909090909~~~ for every eleventh you add to the fraction. At the very end you get .99999~~~ or 11/11 (the real number) which we all know as 1 therefore .9999~~~=1.

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Doghealer

Senior Member

Quote:
Originally Posted by Griftrix